If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2+2x-261=0
a = 3; b = 2; c = -261;
Δ = b2-4ac
Δ = 22-4·3·(-261)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-56}{2*3}=\frac{-58}{6} =-9+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+56}{2*3}=\frac{54}{6} =9 $
| 2n-3=7/ | | 3x-2/3=5+1/3 | | z+5=3z-21 | | 8(2x+9)=59 | | 9(x-2=x-6 | | 5v-10/v-6=2.5 | | 32x-7-5=4 | | 746=x+92 | | 10-4x+12=1 | | 3x^+12x=0 | | 8+5a=48 | | 5x-262x+1=43 | | 16u+18=18u-4 | | 1/4(8k-12)=10 | | 2(2x-1)=2x-6 | | 5-1y=3+1y | | 11-2x=1x-1 | | 3+x/5+5=9 | | m+21=11 | | (2x-1)=2x+62 | | (x)1/2-10=150 | | (2x-1)=2x+6 | | @(2x-1)=2x+6 | | t^2-4t-16.3=0 | | 1x+6=-2x-12 | | 10k-0.7(9k+6)=4k-23 | | (6v-50)+(4v+30)=180 | | 20+30x=36+28x+4x | | x+8+x+8=16 | | (1/2(-4+6x)=(1/3x)+(2/3(x+9) | | 3(x-3)/7+3=3 | | 4*(9v+5)=-32+6v |